A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?(1 point)

Question

Responses

370 N
370 N

380 N
380 N

70 N
70 N

80 N

Answer 1

To find the net force acting on the boy, we can use the following formula:

\[ \text{Net Force} = \text{Applied Forces} - \text{Resistance Forces} \]

1. Applied Forces:

   • The boy's exerted force: 300 N (in one direction)
   • The friend's pulling force: 75 N (in the same direction)

   Total applied force = 300 N + 75 N = 375 N

2. Resistance Forces:

   • The frictional force: 5 N (in the opposite direction)

   Resistance force = 5 N

Now, we can calculate the net force:

\[ \text{Net Force} = 375 N - 5 N = 370 N \]

So, the magnitude of the net force acting on him is 370 N.