KE =PE
m•v²/2 =m•g•h
h = v²/2•g =(35)²/2•9.8 =62.5 m
A boy fires a 60 g pebble with his slingshot. The pebble leaves the slingshot at 35m/s
How high above the slingshot will the pebble rise if it's fired straight up?
2 answers
V2 2 = V1 2 + 2aΔd
0 = 35 2 + 2(-9.8)d
0 = 1225 – 19.6d
-1225 = -19.6d
62.5 = d
The pebble will reach a maximum height of 62.5m [up].
0 = 35 2 + 2(-9.8)d
0 = 1225 – 19.6d
-1225 = -19.6d
62.5 = d
The pebble will reach a maximum height of 62.5m [up].
0 answers