From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The initial speed of the pebble is 7.56 m/s. (a) What is the acceleration (magnitude and direction) of the pebble during the downward motion? (b) After 0.950 s, how far beneath the cliff top is the pebble?

asked by Anonymous

10 years ago

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1 answer

a. -9.8m/s^2

b. d=vi*t+ 1/2 at^2=-7.56*t-4.96t^2

answered by bobpursley

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Question

From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The initial speed of the pebble is 7.56 m/s. (a) What is the acceleration (magnitude and direction) of the pebble during the downward motion? (b) After 0.950 s, how far beneath the cliff top is the pebble?

1 answer

a. -9.8m/s^2

b. d=vi*t+ 1/2 at^2=-7.56*t-4.96t^2

Ask a New Question or answer this question.

bobpursley · Answer

a. -9.8m/s^2 b. d=vi*t+ 1/2 at^2=-7.56*t-4.96t^2