A box of mass 0.385 kg slides down a very smooth (frictionless) ramp which is inclined at an angle of 56.6° above the horizontal. What is the acceleration of the box down the ramp?

Answer 1

The Sum of Forces going down the ramp is equal to mg*sin*(theta). Mass * Acceleration = mg*sin (theta). since the masses are equal for both sides of the equation, you can write the equation as acceleration = g* sin (theta). and sove for the acceleration.

Answer 2

Xdf