which at 2 and which at 8?
assuming the small one is at 2
and the big one at 8
normal force = 9.81 N
friction force = .4*9.81 = 3.92 N
forward force on top small block = 3.92
a of small block = 3.92/1 = 3.92 m/s^2
so speed of small block = 2 + 3.92 t
back force on big block = -3.92 N
a of big block = - 3.92/2 = -1.96 m/s^2
so speed of big blok = 8 - 1.96 t
so we want to know t when
2 + 3.92 t = 8 - 1.96 t
A block of 1kg is kept on another block of 2kg in a horizontal surface. Coefficient of friction between two blocks is 0.4. The blocks are given velocities of 2m/s and 8m/s in same direction.The time when relative motion between them will stop =..???
1 answer
1 answer