a force F is applied in horizontal to a 10kg block. the block moves at a constant speed 2m/s across a horizontal surface. the coefficient of kinetic friction between the block and the surface is 0.5. the work done by the force F in 1.5 minutes is?

Answer 1

work=force*distance
= 10*g*.5*2*1.5min*60sec/min

Answer 2

9000

Answer 3

fn*m(coeffient of friction) = f(friction)
100*.5=50

Make velocity graph, convert 1.5min to seconds (60*1.5=90sec)
since constant, no acceleration
graph should look like rectangle v=2 on y axis t=90 on x axis
multiply like rectangle (2*90=180)
180 meters is the result
W=F*D
W=50 * 180
W=9000J
hope this helps <3

Answer 4

ggez