Asked by Joel
A Force,F=10N,applied at an angle of 37 degree above the horizontal,moves a crate a distance of 5m along a rough horizontal surface.A frictional force of 5N opposes the motion.what is the change in kinetic energy?
Answers
Answered by
bobpursley
net force= 10*cos37-5
That is the net force, operating on a deistance of 5 meters. So that is the change in KE. netforce*distance
That is the net force, operating on a deistance of 5 meters. So that is the change in KE. netforce*distance
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