a= Fnet/Mass
Net force = 0.5*60 + 0.5*40 = 50N
Total mass= 6kg + 4kg = 10kg
a = 50N/10kg = 5m/s^2
a block of mass 6 kg resting on a horizontal surface is connected by a cord passing over a light, frictionless pulley to a hanging block of mass 4 kg. the coefficient of kinetic friction between the block and the horizontal surface is 0.5. after the block are released, find the acceleration of each block and the tension in the cord.
so Wa=6 kg
fk=0.5*6=3
Wb=4 kg
i don't know the next step...
1 answer
1 answer