If this baseball is propelled upwards with a velocity of 30 ft/s, then the formula for its' height after t seconds would be:
h(t)=-16t²+30t+6
It's maximum height is reached at -b/2a seconds, from the equation h(t)=a(t)²+b(t)+c. In this case, that would be -30/-32, or 0.9375 seconds. Then; calculating it's maximum height gives us 20.0625 ft.
If h(t)=0 (i.e., when it finally lands, we have:
-16t²+30t+6=0
16t²-30t-6=0
t=2.05727955 secs
So the range is from t=0 to t=2.05727955 secs.
A baseball is thrown into the air with an upward velocity of 30 ft/s. Its height h, in feet, after t seconds is given by the function h=-16t^2+6. How long will it take the ball to reach its maximum height? What is the ball's maximum height? What is the range of the function?
If somebody could help me with this problem & explain how to do it I would really appreciate it.
4 answers
Thank you so much you're a lifesaver
lol we all here from the same book
I checked this, the problem says, "Round to the nearest hundredth" and says that 2.06 is wrong, can someone help me understand why?
2 answers