Question
a .300 kg baseball is thrown at a speed of 6.5m/s. the batter hits the ball and it flies into the outfield at a speed of 19.2 m/s. How much work is done into hitting the baseball
Answers
work in = change in kinetic energy
= (1/2)m(v2^2 -v1^2)
= (1/2)m(v2^2 -v1^2)
((1/2)M(Vf^2))-((1/2)M(Vi^2))
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