Question
A baseball is thrown at 40 m/s. Jose Bautista hit it back in the opposite direction at a speed of 65 m/s. The ball is in contact for 1.2 ms. What distance does the ball travel while it is in contact with the bat?
Answers
Damon
a = change in velocity/time
= 105/1.2*10^-3 = (105/1.2)10^3
x = 40(1.2)10^-3 - (1/2)at^2
= 40*1.2*10^-3 -(105/2.4)10^3 (1.2)^2 10^-6
= 105/1.2*10^-3 = (105/1.2)10^3
x = 40(1.2)10^-3 - (1/2)at^2
= 40*1.2*10^-3 -(105/2.4)10^3 (1.2)^2 10^-6