A .140 kg baseball is thrown with a velocity of 41.4 m/s. it is struck with an average force of 5000N, which results in a velocity of 37 m/s in the opposite direction. How long were the bat and ball in contact?

Question

A .140 kg baseball is thrown with a velocity of 41.4 m/s.  it is struck with an average force of 5000N, which results in a velocity of 37 m/s in the opposite direction.  How long were the bat and ball in contact?

drwls · Answer

(Avg. Force)(Contact time) = Momentum change of baseball) 5000 kg*m/s^2 *(Time)=(0.140)(41.4+37) = 10.98 kg m/s Time = 0.0022 s