Ask a New Question

Asked by Mike

A .140 kg baseball is thrown with a velocity of 41.4 m/s. it is struck with an average force of 5000N, which results in a velocity of 37 m/s in the opposite direction. How long were the bat and ball in contact?
12 years ago

Answers

Answered by drwls
(Avg. Force)(Contact time) = Momentum change of baseball)
5000 kg*m/s^2 *(Time)=(0.140)(41.4+37)
= 10.98 kg m/s
Time = 0.0022 s
12 years ago

Related Questions

A baseball is thrown up in the air from a height of 3 feet with an initial velocity of 23 feet per s... A 0.105 kg baseball is thrown upward with an initial speed of 12.0 m/s. (a) What is the force on th... A baseball is thrown into the air as shown below. Which is true about the total energy at po... A baseball is thrown into the air as shown below. Which is true about the total energy at po... A baseball is thrown into the air as shown below. Which is true about the total energy at po... A baseball is thrown into the air as shown below witch is true about the total energy at point a A baseball is thrown into the air. what is true about the total energy at point s A baseball is thrown into the air. what is true about the total energy at point s At point S the...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use