Asked by Mike
A .140 kg baseball is thrown with a velocity of 41.4 m/s. it is struck with an average force of 5000N, which results in a velocity of 37 m/s in the opposite direction. How long were the bat and ball in contact?
Answers
Answered by
drwls
(Avg. Force)(Contact time) = Momentum change of baseball)
5000 kg*m/s^2 *(Time)=(0.140)(41.4+37)
= 10.98 kg m/s
Time = 0.0022 s
5000 kg*m/s^2 *(Time)=(0.140)(41.4+37)
= 10.98 kg m/s
Time = 0.0022 s
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