using same method as your other problem, but only up this time
Vi = 100 sin A
v = Vi - 9.81 t
v = 0 at top
so t = 100 sin A/9.81 at top (time of flight is 2 t of course)
h = 100 sin A * t - 4.9 t^2
h = 100^2 sin^2A / 9.81 - (9.81/2) * 100^2 sin^2A/9.81^2
h = (1/2)(100^2)sin^2 A /9.81 = 150
so
sin^2 A = 300 * 9.81 /100^2 = .294
sin A = .542
A = 33 degrees
now for range
use time = 2 t
and range = 100 cos A * 2 t
A ball thrown with a speed of 100 m/s attains a height of 150 m.calculate (a) the time of flight (b) the angle of projection (c) the range
1 answer
1 answer