speed = 100 m/s?
H = 150 m ?
upward trip, t = half flight time
0 = Vi - 9.81 t
t = Vi/9.81
150 = Vi t - (1/2)(9.81) t^2
150 = Vi^2/9.81 - (1/2)(9.81)(Vi^2/9.81^2)
150 = Vi^2 / 4.9
Vi = 27.1 m/s
then t = 27.1/9.81 = 2.76 going up
plus another 2.76 down
---> 5.53 seconds flight time
sin theta = 27.1/100
theta = 15.7 degrees above horizontal
u = 100 cos 15.7
= 96.3 meters/second horizontal
for 5.53 seconds
range = 532 meters down range
A BALL THROWN WITH A SPEED OF 100M ATTAINS A HEIGHT OF 150 CALCULATE (A) THE TIME OF FLIGHT (B) RANGE (C) THE ANGLE
1 answer
1 answer