a ball thrown vertically upward lands on the thrower's hand 24.5s. find (a) the time taken by the ball to reach its maximum height,(b) the maximum height attained by the ball, and (c) initial velocity of the ball

Answer 1

goes up for 24.5/2 seconds
(by the way, no way! )

v = Vi - 9.81 t
v = 0 at top
so
Vi = -9.81(12.25)

h = Vi t - 4.9 t^2
h = Vi (12.5) - 4.9(12.5)^2

Answer 2

i dont no because i want a sulotion plz