A ball of mass 1.20kg falls vertically and hits a horizontal floor at 2.50m/s . The ball then rebounds upward at 10.00m/s . If the ball is in contact with the floor for 0.02 seconds, compute the average force exerted on the floor.
2 answers
It bounced up faster than it fell down?
m=4Kg , v=6m/s momentum changed in 48 kg m/s