That cant be right. A ball gains velocity going down.
Figure the vertical velocity at the floor: 21.1*sin30
Now, that is vfinal. Solve for vintialy here
vfinaly= vinitialy+ 2*9.8*4.66
That will give you the initial vertical velocity. The intial horiontal velocity will be the same as the final horizontal velocty, 21.2 cos30.
Now, you can find the intial velocity.
A volleyball player spikes the ball. The ball hits the floor with a velocity of 21.2 m/s at 30 degrees above the horizontal floor, 4.66 m away from where she spiked it. What was the ball's initial velocity (immediately after the player hits the ball)? Give a magnitude and sketch the direction.
first I used the equation
Vfinal ^2 - Vinitial^2= 2(xfinal-xinitial)
so...
(21.1 m/s)^2 - Vinitial^2 = 2(9.8m/s)(4.66-0)
445.21- Vinitial = (-19.6)(-4.66)
445.21- Vinitial = -91.336
Vinitial = 23.16 m/s
Is this how I would figure it out becuase I'm kind of lost
2 answers
Thank you very much for the help. So i figured out that the vertical initial velocity was 4.47 m/s and the horizontal initial velocity is the same as the final velocity, so it would be 18.27 m/s. So do I need to use both the vertical and horizontal velocties to find the initial velocity or do I just need to worry about the vertical velocity..would I add them? Im sorry, I'm confused