S=at/2.
77=5t^2
t=15.4s
range=vt
R=261.8m
A ball is thrown horizontally of a cliff. If the initial speed of the ball is 17 m/s and the cliff is 77 m high, how far from the base of the cliff will the ball land in the water below? Calculate the answer in meters (m) and rounded to three significant figures.
1 answer
1 answer