A ball is thrown horizontally of a cliff. If the initial speed of the ball is 24.0 m/s and the cliff is 124.0 m high, how far from the base of the cliff will the ball land in the water below? Calculate the answer in meters (m) and rounded to three significant figures.

Answer 1

u = 24 m/s forever

x = u t where t is time to fall 124 m

h = (1/2)g t^2
124 = 4.9 t^2
t = 5.03 seconds
so
x = 24 * 5.03 = 121 meters