A ball is thrown horizontally from the top of a cliff 50m high with a velocity of 7m/s. How far from the base of the building does the ball land.

Question

This is what I think is how you do the question(Please correct me if I am wrong).

y=vt+.5a(t)²
50=0+.5(9.8)t²
10.204=t²
t=3.194 seconds

x=vt+.5a(t)²
x=(7)(3.194)+.5(0)(3.194)²
x=22.36 m

So is the answer 22.36m?

Please help me if I go wrong

Answer 1

time is right. Howver, on the horizontal equation, a=0
x=vt