A 905 kg test car travels around a 3.34 km circular track. If the magnitude of the force that maintains the car’s circular motion is 2134 N, what is the car’s tangential speed? Answer in units of m/s.
3 answers
I am unsure how to solve for V when given the circumference instead of the radius.
Ac = v^2/R
m Ac = m v^2/R = 2134
so
905 v^2/R = 2134
but 2 pi R = 3340 so R = 3340/2pi
so
905 * 2 * pi * v^2 = 2134 * 3340
m Ac = m v^2/R = 2134
so
905 v^2/R = 2134
but 2 pi R = 3340 so R = 3340/2pi
so
905 * 2 * pi * v^2 = 2134 * 3340
Hey what? circumference = 2 pi R :)
3 answers