A car travels at a constant speed around a circular track whose radius is 3.5 km.The car goes once around the track in 400 s.What is the magnitude of the centripetal acceleration of the car?

Answer 1

v^2/r

v = 2 pi r /T = 2 pi (3500/400)

v = 55 m/s

v^2/r = 55^2/3500 = .864 m/s^2