A 905 kg test car travels around a 3.25 km circular track. If the magnitude of the centripetal force is 2140 N, what is the car’s speed?

Answer 1

To find the car's speed, we can use the formula for centripetal force:

F = mv²/r

Where:
F = centripetal force (2140 N)
m = mass of the car (905 kg)
v = velocity of the car
r = radius of the circular track (3.25 km or 3250 m)

Now we can rearrange the formula to solve for v:

v = √(Fr/m)

v = √(2140 * 3250 / 905)
v = √(7375000 / 905)
v = √8154.14
v ≈ 90.3 m/s

Therefore, the car's speed is approximately 90.3 m/s.