A 7.00 kg cannonball is traveling at a velocity of 75.0 m/s at a height of 80.0 m. What is its kinetic energy?(1 point)

Responses

5500 J
5500 J

39,400 J
39,400 J

525 J
525 J

19,700 J

1 answer

To calculate the kinetic energy (KE) of the cannonball, we can use the kinetic energy formula:

\[ KE = \frac{1}{2} mv^2 \]

where:

  • \( m \) is the mass of the object (in kg)
  • \( v \) is the velocity of the object (in m/s)

Given:

  • \( m = 7.00 , \text{kg} \)
  • \( v = 75.0 , \text{m/s} \)

Substituting the values into the formula:

\[ KE = \frac{1}{2} \times 7.00 , \text{kg} \times (75.0 , \text{m/s})^2 \]

Calculating \( (75.0)^2 \):

\[ (75.0)^2 = 5625 , \text{m}^2/\text{s}^2 \]

Now, substituting that back into the kinetic energy formula:

\[ KE = \frac{1}{2} \times 7.00 \times 5625 = 3.5 \times 5625 \]

Calculating \( 3.5 \times 5625 \):

\[ KE = 19687.5 , \text{J} \]

Rounding this to the nearest whole number gives:

\[ KE \approx 19,688 , \text{J} \]

The closest option provided is 19,700 J.