Assume you have a canon aimed straight up. The cannonball is shot at a velocity

of v_0=69 m/s.
How high does the cannonball go?
How much time does it take the cannonball to reach that height?

1 answer

V^2 = Vo^2 + 2g*h.
0 = 69^2 - 19.6h, h = ?.

V = Vo + g*t.
0 = 69 - 9.8t, t = ?.