A 7.00kg cannonball is traveling at a velocity of 75.0 m/s at a height of 80.0 m. What is its kinetic energy?

answers:
19,700 J
39,400 J
5500 J
525 J

1 answer

To calculate the kinetic energy (KE) of the cannonball, you can use the kinetic energy formula:

\[ KE = \frac{1}{2} m v^2 \]

where:

  • \( m \) is the mass of the object (in kg),
  • \( v \) is the velocity of the object (in m/s).

Given:

  • \( m = 7.00 , \text{kg} \)
  • \( v = 75.0 , \text{m/s} \)

Substituting the values into the formula:

\[ KE = \frac{1}{2} \times 7.00 , \text{kg} \times (75.0 , \text{m/s})^2 \]

Calculating \( (75.0 , \text{m/s})^2 \):

\[ 75.0^2 = 5625 , \text{m}^2/\text{s}^2 \]

Now substituting this back into the kinetic energy formula:

\[ KE = \frac{1}{2} \times 7.00 , \text{kg} \times 5625 , \text{m}^2/\text{s}^2 \]

Calculating:

\[ KE = \frac{1}{2} \times 7.00 \times 5625 = 3.5 \times 5625 = 19687.5 , \text{J} \]

Rounding to the appropriate significant figures, it is approximately:

\[ KE \approx 19700 , \text{J} \]

So the answer is:

19,700 J.