for (a) just conserve momentum:
(66.5+0.14)*2.09 = 66.5v + 0.14*22.5
v = 2.047
do (b) the same way. just consider the snowball and the skater before and after the collision.
A 66.5 kg ice skater moving to the right with a velocity of 2.09 m/s throws a 0.14 kg snowball to the right with a velocity of 22.5 m/s relative to the ground.
(a) What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.
m/s to the right
(b) A second skater initially at rest with a mass of 61.00 kg catches the snowball. What is the velocity of the second skater after catching the snowball in a perfectly inelastic collision?
m/s to the right
1 answer