Asked by Sarah
a 65-kg ice skater moving to the right with a velocity of 2.50m/s throws a .150kg snowball to the right with a velocity of 32.0m/s relative to the ground
a) what is the velocity of the ice skater after throwing the snowball?
b) a second skater initially at rest with a mass of 60kg catches the snowball. What is the velocity of the second skater after catching the snowball?
a) what is the velocity of the ice skater after throwing the snowball?
b) a second skater initially at rest with a mass of 60kg catches the snowball. What is the velocity of the second skater after catching the snowball?
Answers
Answered by
Elena
m1=65 kg, m2 =0.15 kg, m3 = 60 kg,
v1 = 2.5 m/s, v2 = 32 m/s.
(m1 + m2)•v1 =m2•v2 + m1•u,
u = {(m1+m2) •v1 – m2•v2}/m1 = {65.15•2.5 -0.15•32}/65 = 2.43 m/s,
m2•v2 = (m2+m3) •u1,
u1 = m2•v2/(m2+m3) = 0.15•32/(60+0.15) =
= 0.08 m/s.
v1 = 2.5 m/s, v2 = 32 m/s.
(m1 + m2)•v1 =m2•v2 + m1•u,
u = {(m1+m2) •v1 – m2•v2}/m1 = {65.15•2.5 -0.15•32}/65 = 2.43 m/s,
m2•v2 = (m2+m3) •u1,
u1 = m2•v2/(m2+m3) = 0.15•32/(60+0.15) =
= 0.08 m/s.
Answered by
Abby
I’m concerned what u mean by adding the letter “u” in this equation
Answered by
Kenna R Aga
3.9
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