A 625-kg racing car completes one lap in 14.3 s around a circular track with a radius of 50.0 m. The car moves at constant speed.
(a) What is the acceleration of the car?
5 answers
Your SUBJECT is not 11th grade.
yes it is
acceleration= V^2/r
v=PI*r*2/14.3
so acceleration= PI^2*4*r/14.3 put r in.
check my algebra.
v=PI*r*2/14.3
so acceleration= PI^2*4*r/14.3 put r in.
check my algebra.
Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)^2)/r
= ((2*3.14*50/14.3)^2)/50
= 9.64 m/s^2
= (circumference/time)^2/r
= (2*pi*r/t)^2)/r
= ((2*3.14*50/14.3)^2)/50
= 9.64 m/s^2
Thank you! you are correct @carey
2 answers