A 590 kg racing car completes one lap in 14.3 seconds around a circular track with a radios of 45.0 meters. The car moves at constant speed. (A) what is the acceleration of the car? (B) what force must the track exert on the tires to produse this acceleration?

Answer 1

the answer is 0.44 rad/sec.

This is true because the equation for angular velocity is w = (theta)/(time). Since we know theta of a circle is 2pi, and the time is 14.3 seconds, we can just plug the numbers in.

w = 2pi / 14.3 = 0.44 rad/sec.

Answer 2

98