(a^6 x a^6)^k = (a^3)^(k+5)

Solve for k.
a. 3/2
b. 5/3
c. 2
d. 3
e. 5

I think when simplified its (a^12)^k = (a^3)^(k+5)
but i don't know how to get k from here. How do you solve for these kind of exponents?

2 answers

a^12 = (a^3)^4, so

(a^3)^(4k) = (a^3)^(k+5), so
4k = k+5
k = 5/3
Thank you so much :D
Similar Questions
    1. answers icon 1 answer
  1. Combine like terms:-3x^2+2x-4x^2-9+6x-2x^2+8 Solve for x: 8x-11= -11x+18 Solve for x: -2(x-5)+7=z-8-5x Solve for x: (x-2)/5 -
    1. answers icon 8 answers
  2. Solve the indicated variable:1. Volume of a cone: solve for h: V=¨ir^2h/3 2. Temperature formula: solve for C: F=9/5C+32
    1. answers icon 1 answer
  3. Put in the correct orderSolve exponentiation. Solve multiplication and division. Solve operations within parentheses Solve
    1. answers icon 1 answer
more similar questions