Anonymous150

(a^6 x a^6)^k = (a^3)^(k+5) Solve for k. a. 3/2 b. 5/3 c. 2 d. 3 e. 5 I think when simplified its (a^12)^k = (a^3)^(k+5) but i don't know how to get k from here. How do you solve for these kind of exponents?

Thank you so much :D

9x-y=72 x+4y=45 get either x to be same value or y... in this case i chose y 4(9x-y=72) x+4y=45 so 36x-4y=288 x+4y=45 so 37x=333 x= 9 then plug 9 into one of the equation to get y.