A 50-gram glass holds 400 grams of liquid water and 75 grams of ice. After 20 minutes the mass of ice is 50 grams. Assuming that no evaporation or sublimation has occurred, calculate the mass of the liquid water at this time and EXPLAIN how this is found in simple terms.

Answer 1

To calculate the mass of the liquid water after 20 minutes, we first need to understand the initial mass and the changes that occur during this time.

Initial Scenario:

• Mass of glass = 50 grams
• Mass of liquid water = 400 grams
• Mass of ice = 75 grams

Total initial mass: The total mass of everything in the glass initially is: \[ \text{Total mass} = \text{Mass of glass} + \text{Mass of liquid water} + \text{Mass of ice} = 50 \text{ g} + 400 \text{ g} + 75 \text{ g} = 525 \text{ grams} \]

After 20 minutes:

• Mass of ice after 20 minutes = 50 grams

Assuming that no evaporation or sublimation has occurred, the mass of water (which includes the ice that has melted) must still equal the initial total mass of the system.

1. Calculate the mass of ice that has melted: \[ \text{Mass of ice melted} = \text{Initial mass of ice} - \text{Remaining mass of ice} = 75 \text{ g} - 50 \text{ g} = 25 \text{ grams} \]

2. Determine the mass of liquid water contributed by the melted ice: When ice melts, it turns into liquid water with the same mass. Therefore, the 25 grams of ice that melted contributes an additional 25 grams to the mass of liquid water.

3. Calculate the final mass of liquid water: Initially, the liquid water was 400 grams. After 20 minutes, we add the 25 grams from the melted ice: \[ \text{Final mass of liquid water} = \text{Initial mass of liquid water} + \text{Mass of ice melted} = 400 \text{ g} + 25 \text{ g} = 425 \text{ grams} \]

Conclusion: After 20 minutes, the mass of the liquid water in the glass is 425 grams. The calculation is based on the principle that the total mass of the system remains constant when there is no loss to the environment, such as evaporation.

Answer 2

Can you explain in simple terms your Conclusion:
"After 20 minutes, the mass of the liquid water in the glass is 425 grams. The calculation is based on the principle that the total mass of the system remains constant when there is no loss to the environment, such as evaporation."

Answer 3

Sure! Let’s break it down in simpler terms:

1. Understanding Mass:

   • We have a glass with some water and ice. The total mass of everything in the glass (the glass itself, the water, and the ice) is what we’re looking at.

2. What Happens After 20 Minutes:

   • After 20 minutes, some of the ice melted. This means that part of the ice (25 grams) has turned into liquid water.
   • The amount of ice left is 50 grams, which means that 25 grams of ice was turned into water.

3. Total Liquid Water:

   • At the start, we had 400 grams of liquid water. Now, we need to add the 25 grams that came from the melted ice.
   • So, we take the original 400 grams of water and add the 25 grams from the melted ice.

4. Calculating Final Water Mass:

   • When we add these together: \[ 400 \text{ grams} (initial water) + 25 \text{ grams} (melted ice) = 425 \text{ grams} (final liquid water) \]

5. No Mass Loss:

   • We assumed that no water evaporated or disappeared. This means all the mass from the system (initially 525 grams) is still there, it just changed forms (some ice became water), but the total amount hasn’t changed.

So, in simple terms, after 20 minutes, you have 425 grams of liquid water because some of the ice melted and added to the amount of water you already had, and nothing was lost or went away during that time!

Answer 4

Thank you

Answer 5

You're welcome! If you have any more questions or if there's anything else I can help you with, feel free to ask. Happy learning!