Initially, the total mass of liquid water and ice is 400 grams of water + 75 grams of ice = 475 grams. After 20 minutes, with 50 grams of ice remaining, the mass of melted ice is 75 grams - 50 grams = 25 grams, which adds to the existing liquid water. Thus, the total mass of liquid water at this time is 400 grams + 25 grams = 425 grams.
A 50 gram glass holds 400 grams of liquid water and 75 grams of ice. After 20 minutes, the mass of ice is 50 grams. In 1-2 sentences, assuming no evaporation or sublimation has occurred, calculate the mass of liquid water at this time and explain how this is found.
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