Question

A 50 gram glass holds 400 grams of liquid water and 75 grams of ice. After 20 minutes the mass of ice is 50 grams. In 1-2 sentences, assuming no evaporation or sublimation has occurred, calculate the mass of the liquid water at this time and explain how this is found. Write like a student.

Answer 1

After 20 minutes, the mass of the liquid water is 425 grams. This is found by adding the initial mass of the liquid water (400 grams) to the mass of the melted ice (50 grams) and assuming that no water was lost to evaporation or sublimation.