gravity down the plane: mgSinTheta
normal to the plane weight: mgCosTheta
constant velocity, no acceleration...
net force=ma=0
mgSinTheta-mu*mgCosTheta=0
divide both sides by CosTheta
mgTanTheta=mu*mg
theta=arctan mu
.: A 5.0 kg block is moving with constant velocity down a rough incline plane. The coefficients of static and kinetic friction between the block and the incline are 0.25 and 0.20, respectively. What is the inclination angle of the incline plane?
4 answers
of course, mu is the kinetic coefficent.
In a collision, an automobile of mass 826 kg stops with constant acceleration in 20 m from an initial speed of 17 m/s.
What is the acceleration of the car in m/s
What is the acceleration of the car in m/s
12 kg box is sliding down an incline and the coefficient of kinetic friction between the box and the incline is 0.11. Find the angle of the incline where the box slides down with a constant velocity.