A block with mass m = 16.3 kg slides down an inclined plane of slope angle 28.0 ° with a constant velocity. It is then projected up the same plane with an initial speed 1.80 m/s. How far up the incline will the block move before coming to rest?

Answer 1

m*g = 16.3*9.8 = 159.74 N.
Fp = 159.74*sin28 = 75 N.
Fn = 159.74*cos28 = 141 N.

Fp-Fk = m*a
75-Fk = m*0 = 0
Fk = 75 N.

KE = 0.5m*V^2 = 0.5*16.3*1.8^2=26.41 J.

Fp*d = KE-Fk*d
75 * d = 26.41-75*d
75d + 75d = 26.41
150d = 26.41
d = 0.176 m.