q = mass H2O x specific heat H2O x (Tfinal-Tinitial).
mass is 50 kg. Chane to g.
q = 333 kJ. Change to J.
Substitute into the equatiion and solve for Tfinal.
Specific heat H2O should be in units of J/g*C which is 4.184 J/g*C
Post your work if you get stuck.
A 5.0×101 kg sample of water absorbs 333 kJ of heat.
If the water was initially at 23.1 ∘C, what is its final temperature?
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