Q=mc∆t
Q = heat energy (in joules) be sure to convert your kJ of heat to J by multiplying by 1000
m = mass (in grams)
be sure to convert your kg of water into grams by multiplying by 1000
c = specific heat (of water)
∆t= change in temperature (= final - initial temp)
c= 4.186 joule/gram °C
A 5.0×101 kg sample of water absorbs 312 kJ of heat.If the water was initially at 20.1C, what is its final temperature?
1 answer