F=ILBsinα
B=F/ILsinα=0.15/67•45•sin51.5⁰=6.35•10⁻⁵ T
A 45-m length of wire is stretched horizontally between two vertical posts. The wire carries a current of 67 A and experiences a magnetic force of 0.15 N. Find the magnitude of the earth's magnetic field at the location of the wire, assuming the field makes an angle of 51.5° with respect to the wire.
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