Hint:
Stress in steel = 40N/1mm^2
Stress in aluminum = 40N/3mm^2
Speed of sound = (stress/density)^1/2
Wavelength × Frequency = Speed
Minimum frequency corresponds to a half wavelength in one of the two wires. Find out which wire and use the corresponding frequency.
9. Figure shows an aluminium wire of length 60 cm joined to a steel wire of length 80 cm and stretched between
two fixed supports. The tension produced is 40 N. The cross-sectional area of the steei wire is 1.0 mm2 and
that of the aluminium wire is 3.0 mm2. The minimum frequency of a tuning fork which can produce standing
waves in the system with the joint as a node is 10P (in Hz) then find P. Given density of aluminium is
2.6 g/cm3 and that of steel is 7.8 g/cm3.
1 answer
0 answers