To find the change in heat content of the system, we first need to calculate the amount of heat required to raise the temperature of the ice to -28 Celsius.
The specific heat capacity of ice is 2.09 J/g°C.
First, we need to determine the amount of heat needed to heat the ice from -58 to 0 Celsius, and then to 0 to -28 Celsius.
Q1 = mass x specific heat capacity x ΔT
Q1 = 445g x 2.09 J/g°C x (0 - (-58)°C)
Q1 = 445g x 2.09 J/g°C x 58°C
Q1 = 5.70274 x 10^4 J
Q2 = mass x specific heat capacity x ΔT
Q2 = 445g x 2.09 J/g°C x (-28 - 0)°C
Q2 = 445g x 2.09 J/g°C x -28°C
Q2 = -2.1171 x 10^4 J
The total change in heat content of the system is the sum of Q1 and Q2.
Total change in heat content = Q1 + Q2
Total change in heat content = 5.70274 x 10^4 J - 2.1171 x 10^4 J
Total change in heat content = 3.58564 x 10^4 J
Therefore, the change in heat content of the system is 3.58564 x 10^4 J.
A 445G sample of ice at -58. Celsius is heated until its temperature reaches -28 Celsius. Find the change in heat content of the system.
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