To find the change in the heat content of the system, we need to calculate the amount of heat added to the water to heat it up from 21°C to 100°C (boiling point) and then from 100°C to 143°C.
First, we calculate the heat required to raise the temperature of the water from 21°C to 100°C.
Q = m * Cp * ΔT
where:
Q = heat added (Joules)
m = mass of water (79g)
Cp = specific heat capacity of water (4.18 J/g°C)
ΔT = change in temperature (100°C - 21°C)
Q1 = 79g * 4.18 J/g°C * (100°C - 21°C)
Q1 = 6,448.38 J
Next, we calculate the heat required to raise the temperature of the water from 100°C to 143°C.
Q2 = m * Cp * ΔT
where:
Q2 = heat added (Joules)
m = mass of water in steam form (79g, since we are assuming no water is lost as steam)
Cp = specific heat capacity of steam (2.03 J/g°C)
ΔT = change in temperature (143°C - 100°C)
Q2 = 79g * 2.03 J/g°C * (143°C - 100°C)
Q2 = 3,396.11 J
Therefore, the total change in heat content of the system is the sum of Q1 and Q2:
ΔQ = Q1 + Q2
ΔQ = 6,448.38 J + 3,396.11 J
ΔQ = 9,844.49 J
Therefore, the change in the heat content of the system is 9,844.49 Joules.
79G sample of water at 21 Celsius is heated until it becomes steam with the temperature of 143 Celsius. Find the change in the heat content of the system.
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