P1V1/T1=P2V2/T2
V2/V1=T2/T1 if P1=P2
T1=273+20=293
therefore, T2= 2*293K
T2= 293C
To what Celsius temperature must a gas sample initially at 20 degrees Celsius be heated if its volume is to double while the pressure remains the same?
4 answers
255
293C
233C