A 400.0 kg mass experiences a horizontal push force of +720 N and a friction force of 320 N.

Question

A) assuming the mass is initially moving at 5.0 m/s how far will it travel in 6.0s?
B) how much work does the 720.0 Newton force do over the distance determined in part (a)
C) calculate the power of the 720.0 N force using the results from part b and the given amount of time.

Answer 1

what do you think the answer is

Answer 2

i'm afraid i cant help you then

Answer 3

a = (F-Fk)/M = (720-320)/400 = 1.0 m/s^2

A. d = Vo*t + 0.5a*t^2.
Vo = 5 m/s.
t = 6 s.
d = ?.

B. Work = F*d.

C. Power = Work/t in J/s = Watts.

Answer 4

a) Fnet=ma
F-Ff=ma
720-320=400a
400=400a
a=1 m.s^-2
x=vt+0.5at^2
x=(5)(6)+0.5(1)(6)^2
x=48 m
b) W=Fxcos¤
=720*43*cos0
= 34560 J
c)P=W/t
=34560/6
=5760 W

HOPE THAT HELPS

Answer 5

Cheater!!!!!!!!!!!!!!!!!!!