Solve the following pair of equations simltaneously:
72 - f = M * 0.43
77 - f = M * 0.58
f is the friction force.
Subtract the first equation from the second:
5 = 0.15 M
M = 33.33 kg
Then solve for f. Use either of the first two equations and plug in the value for M
The coefficient of friction is f/(M*g)
You push a box along the floor against a constant force of friction. When you push with a horizontal force of 72 N the acceleration of the box is 0.43 m/s2; when you increase the force to 77 N the acceleration is 0.58 m/s2.
(a) Find the mass of the box.
(b) Find the coefficient of kinetic friction between the box and the floor.
1 answer
2 answers