A 4.0 gram sample of iron was heated from 0 degrees celsius to 20 degrees celsius, and was found to have absorbed 35.2 Joules of heat. Calculate the specific heat of this piece of iron.

Answer 1

Q=mc∆t
find c.

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Answer 2

Formula for specific heat:q/(m * delta t)
Input given data: 35.2 J/(4.0 g * 20 c)
Solve: 0.44 J/(g*c)