An 80.0-gram sample of a gas was heated from 25 degrees celsius to 225 degrees celsius. During this process, 346j of work was done by the system and its internal energy increased by 7785j. What is the specific heat of the gas?

Answer 1

delta E = delta H + work
7785 = q + (-346)
Solve for q.
Then q = mass x specific heat x (Tfinal-Tinitial)
You know q, mass, Tfinal and Tinitial. Solve for sp. h. .