Asked by Suzy
a 20 ft ladder is leaning against a wall. The bottom is being pulled out at a constant rate of 2.5 ft/sec. Will the top of the ladder clide sown thr wall at a constant rate? What will the rate be? In relation to time?
It is not constant.
Use pythagorus: x^2 + y^2 = l^2, where l is the length of the ladder, and x is the x (horizontal) component, and y is vertical component. Then take the derivatives with respect to time, and solve for dy/dx.
I hope this is enough of a start for you...
Let x by horizontal, y be vertical.
20^2=x^2 + y^2
O=2x dx/dt + 2y dy/dy
You know dx/dt, which is a constant. Solve for dy/dt? is x, y constant (NO).
It is not constant.
Use pythagorus: x^2 + y^2 = l^2, where l is the length of the ladder, and x is the x (horizontal) component, and y is vertical component. Then take the derivatives with respect to time, and solve for dy/dx.
I hope this is enough of a start for you...
Let x by horizontal, y be vertical.
20^2=x^2 + y^2
O=2x dx/dt + 2y dy/dy
You know dx/dt, which is a constant. Solve for dy/dt? is x, y constant (NO).
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.