millimoles MgCl2 = 20 x 0.200 = 4.0
millimoles AgNO3 = 95 x 0.8 = 7.6
.........2AgNO3 + MgCl2 ==> 2AgCl + Mg(NO3)2
The nitrate ions never enter any reaction so they are at the end what they were initially. They were 0.8M but that's been diluted by 95/(95+20)
That is 0.8M x (95/(95+20) = ?
A 20.00 mL of 0.200mol/L magnesium chloride solution is added to a 95.00 mL of 0.800 silver (I) nitrate solution, and a precipitate is formed.
a.Determine the concetration of the nitrate ions at the end of the reaction
I was able to calculate the things and make an IRF table but i don't know what to do after that plz help!
1 answer
1 answer